CompuServe Messages

> Sorry, but it IS compiling a jump to 0x4, I watched it jump to 0x4 >using the debugger. I think it is an indirect JSR call, but since I know >almost no assembler, the assem. source means almost nothing to me. I don't know what the I&D situation is on the Amiga (it's been years since I toyed with that kinda stuff and forget which chips and OSs do what), but there is a big difference in your executing (seeing) a jmp to 4 in your debugger or the compiler generating the jump or the RTL routine doing it or etc. These may seem like pedantic differences, but they all present totally different scenarios. Finding out which is your case is the issue. For instance, perhaps what you're seeing executed is some data somewhere that the program "inadvertantly" got to via some uninitialized function pointer or somesuch. I have a cliche I use often when I lecture on C and C++, more applicable to source but, but it is probably applicable here to: What you see is what you get. — Anonymous What you see is all you get. — Brian Kernighan What you see is what you see. What you get is what you get. — Greg Comeau This (unfortunately?!) encompasses many things, programming and otherwise and is "what the fun is about." 😉