CompuServe Messages

VJ >>How does one determine how much RAM is in on of these SIMMS?<< If they are 8-bit (or 9-bit) SIMMs: A 256×8 SIMM, would be 256 kilobits x 8 bits = 256K per SIMM A 512×8 SIMM, would be 512 kilobits x 8 bits = 512K per SIMM A 1×8 SIMM, would be 1024 kilobits x 8 bits = 1024K (1 meg) per SIMM A 4×8 SIMM, would be 4096 kilobits x 8 bits = 4096K (4 meg) per SIMM. If they are 32-bit (or 36-bit) SIMMs, they will be 72-pin SIMMs: A 256×32 SIMM, would be 256 kbits x 32 bits = 1024K (1-meg) per SIMM A 512×32 SIMM, would be 512 kbits x 32 bits = 2048K (2-meg) per SIMM A 1×32 SIMM, would be 1024 kbits x 32 bits = 4096K (4-meg) per SIMM A 4×32 SIMM, would be 4096 kbits x 32 bits = 16384K (16-meg) per SIMM. A Zorro-II card would use the 8-bit SIMMs. A CPU-card, depending on design would use either the 8-bit, or the 32-bit SIMMs. — JV >>at typing AVAIL. For chip it lists 1047552. How does that number translate to K?<< AVAIL, displays the number of BYTES. If you divide by 1024, you will be given the approximate number in Kilobytes. Divide again by 1024, to get the approximate number of Megabytes. 8 bits = 1 byte 1024 bytes = 1 Kilobyte 1024 kilobytes = 1 Megabyte 1024 megabytes = 1 Gigabyte Its a metric system based on 8 & 1024, instead of 10 & 1000. Ron. – ap'ing with AP. (Eagles may fly, but weasels aren't sucked into jet engines.)