Coefficient/Friction
14-Jul-94 15:36:30
Sb: #112859-Coefficient/Friction
Fm: Tyler Colwell 74352,3010
To: Paul Kakert 73751,3241
Mr Kakert,
The advice given thus far in this thread has been excellent. I wouldn't advise
trying to work in your own version of the accident dynamics; I would stick to
animating according to calculations of a forensic engineer. Having said that,
the following simple formula can be used to predict the approximate "locked
skid distance" for a given initial vehicle velocity. (Contrary to earlier
advice, the vehicle mass is not needed):
0.5 (V^2) where V = vehicle velocity when skid
begins
D = ————– u = coeffiction of sliding
friction between tires
(u) (g) and the road
g = gravitational acceleration (32.2
ft/s^2)
For example, a vehicle travelling at 55 mph (81 ft/s) slams on the brakes and
skids to a stop. If the coefficient of sliding friction between the tires and
the road is 0.75 (varies widely depending road surface conditions and the tire
tread, inflation, etc.), the skid distance would be:
D = 0.5 (81 ft/s)^2 / (0.75) (32.2 ft/s^2) = 134 ft
Or at 65 mph,
D = 188 ft
This is a simplistic evaluation and I only use it for getting a rough idea.
The coefficient of friction is a squirrely value and, as I said, can vary
significantly.
For what it's worth,
-TC