CompuServe Messages

I'm guessing that you don't mean everything that you say. I think that you want an array of pointers to strings (which are themselves arrays of chars). An array, X, of pointers to char *, is declared as char *X[y];, where "y" is the length of the desired array. It absoultely doesn't matter how long any of the strings are. This array is only going to take (y*sizeof(char *)) no matter what any of the pointers point to. What this does is to create an array of "y" pointers. If you haven't auto-initialized your array (told the compiler what strings you want to be pointed to), you could initialize it and use it something like this: main() { char *X[3]; X[0] = "test"; X[1] = "this is"; X[2] = "a"; printf("%s %s %s.\n", X[1], X[2], X[0]); } Looking at your source: First, don't put a declaration in a header. (There are two words I can never remember to keep straight — one is where you tell the compiler about the type of some variable you want to refernce, the other is where you tell the compiler that *and* ask it to set aside memory for the variable — I'm talking about the later.) You could have "extern char *mt_fieldnames[]" in your .h, but you shouldn't have the rest there. I don't get your #define of WHERE. I don't understand the syntax and I don't understand what you are trying to do. Dale Larson – An Amiga Software Engineer with some time on his hands.