CompuServe Messages

Sorry, a char is 8 bits, and an unsigned char is also 8 bits. The range of the two is difference, but they have the same number of bits. And C compilers will put in the unsigned bit pattern, even if it don't fit the range i.e. char c; c = 255; will put the bit pattern 1111 1111 into c, even though that's -1. The reason the compiler is flagging it is that ANSI states that hex character constants continue from the 'x' to the first non-hexadeciaml chracter. Since 9b0 is greater than a character, in size, the compiler spits out a warning message. The way to split things up is to either use string concatenation, or to make sure the hex constant isn't followed by something which could be interpreted as a hexadecimal character. -Mike