CompuServe Messages

>If you were going to add 512K, to an 8-bit buss, you would only need two >256K 8-bit SIMMs. To create two banks of 256K. > >If you were going to add 512K, to a 16-bit buss, you would only need two >256K 8-bit SIMMs. to create one bank of 256K. The two 8-bit SIMMs would >give 16-bits. PI >>I don't understand this – you have 1 bank of 256k in the second example. Wouldn't it be 2 8bit chips together giving 1 512k 16bit wide bank?<< OOOOOOOPS!!!!! When I proof read my replies, I always seem to overlook the math. That should have said, 'If you were going to add 512K, to an 8-bit buss, you would only need two 256K 8-bit SIMMs. To create two banks of 256K. If you were going to add 512K, to a 16-bit buss, you would only need two 256K 8-bit SIMMs. To create one bank of 512K. The two 8-bit SIMMs would give 16-bits.' However, you caught the mistake, so you really did understand. Ron. – ap'ing with AP. (Eagles may fly, but weasels aren't sucked into jet engines.)